1-(3x+7)=4(x-3)-(x+2(x-5))

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Solution for 1-(3x+7)=4(x-3)-(x+2(x-5)) equation: 



1-(3x+7)=4(x-3)-(x+2(x-5))

We move all terms to the left:

1-(3x+7)-(4(x-3)-(x+2(x-5)))=0

We get rid of parentheses

-3x-(4(x-3)-(x+2(x-5)))-7+1=0



We calculate terms in parentheses: -(4(x-3)-(x+2(x-5))), so:

4(x-3)-(x+2(x-5))

We multiply parentheses

4x-(x+2(x-5))-12



We calculate terms in parentheses: -(x+2(x-5)), so:

x+2(x-5)

We multiply parentheses

x+2x-10

We add all the numbers together, and all the variables

3x-10

Back to the equation:

-(3x-10)



We get rid of parentheses

4x-3x+10-12

We add all the numbers together, and all the variables

x-2

Back to the equation:

-(x-2)



We add all the numbers together, and all the variables

-3x-(x-2)-6=0

We get rid of parentheses

-3x-x+2-6=0

We add all the numbers together, and all the variables

-4x-4=0

We move all terms containing x to the left, all other terms to the right

-4x=4

x=4/-4

x=-1

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