1-(3x-4)=(7x+3)/5

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Solution for 1-(3x-4)=(7x+3)/5 equation: 



1-(3x-4)=(7x+3)/5

We move all terms to the left:

1-(3x-4)-((7x+3)/5)=0

We get rid of parentheses

-3x-((7x+3)/5)+4+1=0

We multiply all the terms by the denominator


-3x*5)-((7x+3)+4*5)+1*5)=0

We add all the numbers together, and all the variables

-3x*5)-((7x+3)=0

Wy multiply elements

-15x^2=0

a = -15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-15)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-30}=0$

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