1-(8x2=)-5

Solution for 1-(8x2=)-5 equation:

1-(8x^2=)-5

We move all terms to the left:

1-(8x^2-()-5)=0


We calculate terms in parentheses: -(8x^2-()-5), so:

8x^2-()-5

determiningTheFunctionDomain
8x^2-5-()

We add all the numbers together, and all the variables

8x^2

Back to the equation:

-(8x^2)


a = -8; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-8)·1
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{2}}{2*-8}=\frac{0-4\sqrt{2}}{-16}
=-\frac{4\sqrt{2}}{-16}
=-\frac{\sqrt{2}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{2}}{2*-8}=\frac{0+4\sqrt{2}}{-16}
=\frac{4\sqrt{2}}{-16}
=\frac{\sqrt{2}}{-4}
$