1-(b+2)=-7(4b+4)

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Solution for 1-(b+2)=-7(4b+4) equation: 



1-(b+2)=-7(4b+4)

We move all terms to the left:

1-(b+2)-(-7(4b+4))=0

We get rid of parentheses

-b-(-7(4b+4))-2+1=0



We calculate terms in parentheses: -(-7(4b+4)), so:

-7(4b+4)

We multiply parentheses

-28b-28

Back to the equation:

-(-28b-28)



We add all the numbers together, and all the variables

-1b-(-28b-28)-1=0

We get rid of parentheses

-1b+28b+28-1=0

We add all the numbers together, and all the variables

27b+27=0

We move all terms containing b to the left, all other terms to the right

27b=-27

b=-27/27

b=-1

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