1-(k+2)/2-(k-3)=2

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Solution for 1-(k+2)/2-(k-3)=2 equation: 


k in (-oo:+oo)

1-((k+2)/2)-k+3 = 2 // - 2

1-((k+2)/2)-k-2+3 = 0

(-1*(k+2))/2-k-2+1+3 = 0

(-1*(k+2))/2+(2*(-k))/2+(-2*2)/2+(1*2)/2+(2*3)/2 = 0

2*(-k)-1*(k+2)-2*2+1*2+2*3 = 0

2-3*k-4-2+6 = 0

2-3*k-6+6 = 0

6-3*k-4 = 0

2-3*k = 0

(2-3*k)/2 = 0

(2-3*k)/2 = 0 // * 2

2-3*k = 0

2-3*k = 0 // - 2

-3*k = -2 // : -3

k = -2/(-3)

k = 2/3

k = 2/3

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