1-(x-2)-((x-3)-(x-1))=0

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Solution for 1-(x-2)-((x-3)-(x-1))=0 equation: 



1-(x-2)-((x-3)-(x-1))=0

We get rid of parentheses

-x-((x-3)-(x-1))+2+1=0



We calculate terms in parentheses: -((x-3)-(x-1)), so:

(x-3)-(x-1)

We get rid of parentheses

x-x-3+1

We add all the numbers together, and all the variables

-2

Back to the equation:

-(-2)



We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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