1-1(2n+9)=4(1n-2)

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Solution for 1-1(2n+9)=4(1n-2) equation: 



1-1(2n+9)=4(1n-2)

We move all terms to the left:

1-1(2n+9)-(4(1n-2))=0

We add all the numbers together, and all the variables

-1(2n+9)-(4(n-2))+1=0



We calculate terms in parentheses: -(4(n-2)), so:

4(n-2)

We multiply parentheses

4n-8

Back to the equation:

-(4n-8)



We get rid of parentheses

-1(2n+9)-4n+8+1=0

We add all the numbers together, and all the variables

-4n-1(2n+9)+9=0

We move all terms containing n to the left, all other terms to the right

-4n-1(2n+9)=-9

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