1-12/7z=48

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Solution for 1-12/7z=48 equation: 



1-12/7z=48

We move all terms to the left:

1-12/7z-(48)=0



Domain of the equation: 7z!=0

z!=0/7

z!=0

z∈R



We add all the numbers together, and all the variables

-12/7z-47=0

We multiply all the terms by the denominator


-47*7z-12=0

Wy multiply elements

-329z-12=0

We move all terms containing z to the left, all other terms to the right

-329z=12

z=12/-329

z=-12/329

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