1-13x2+25-3+15-3=x

Solution for 1-13x2+25-3+15-3=x equation:

1-13x^2+25-3+15-3=x

We move all terms to the left:

1-13x^2+25-3+15-3-(x)=0

We add all the numbers together, and all the variables

-13x^2-1x+35=0

a = -13; b = -1; c = +35;
Δ = b2-4ac
Δ = -12-4·(-13)·35
Δ = 1821
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1821}}{2*-13}=\frac{1-\sqrt{1821}}{-26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1821}}{2*-13}=\frac{1+\sqrt{1821}}{-26}
$