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1-2(2/5x+1)=-4/5(1+x)
We move all terms to the left:
1-2(2/5x+1)-(-4/5(1+x))=0
Domain of the equation: 5x+1)!=0
x∈R
Domain of the equation: 5(1+x))!=0We add all the numbers together, and all the variables
x∈R
-2(2/5x+1)-(-4/5(x+1))+1=0
We multiply parentheses
-4x-(-4/5(x+1))-2+1=0
We multiply all the terms by the denominator
-4x*5(x+1))-(-2*5(x+1))+1*5(x-4+1))=0
We add all the numbers together, and all the variables
-4x*5(x+1))-(-2*5(x+1))+1*5(x-3))=0
We add all the numbers together, and all the variables
-4x*5(x+1))-(-2*5(x+1))+1*5(x=0
Wy multiply elements
-20x^2(x-50x^2(x=0
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