1-2(3a-5)=3(-2a+1)+8

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Solution for 1-2(3a-5)=3(-2a+1)+8 equation: 


Simplifying
1 + -2(3a + -5) = 3(-2a + 1) + 8

Reorder the terms:
1 + -2(-5 + 3a) = 3(-2a + 1) + 8
1 + (-5 * -2 + 3a * -2) = 3(-2a + 1) + 8
1 + (10 + -6a) = 3(-2a + 1) + 8

Combine like terms: 1 + 10 = 11
11 + -6a = 3(-2a + 1) + 8

Reorder the terms:
11 + -6a = 3(1 + -2a) + 8
11 + -6a = (1 * 3 + -2a * 3) + 8
11 + -6a = (3 + -6a) + 8

Reorder the terms:
11 + -6a = 3 + 8 + -6a

Combine like terms: 3 + 8 = 11
11 + -6a = 11 + -6a

Add '-11' to each side of the equation.
11 + -11 + -6a = 11 + -11 + -6a

Combine like terms: 11 + -11 = 0
0 + -6a = 11 + -11 + -6a
-6a = 11 + -11 + -6a

Combine like terms: 11 + -11 = 0
-6a = 0 + -6a
-6a = -6a

Add '6a' to each side of the equation.
-6a + 6a = -6a + 6a

Combine like terms: -6a + 6a = 0
0 = -6a + 6a

Combine like terms: -6a + 6a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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