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1-2(5-2x)=5x-5-x+(-4)
We move all terms to the left:
1-2(5-2x)-(5x-5-x+(-4))=0
We add all the numbers together, and all the variables
-2(-2x+5)-(5x-5-x+(-4))+1=0
We multiply parentheses
4x-(5x-5-x+(-4))-10+1=0
We calculate terms in parentheses: -(5x-5-x+(-4)), so:We add all the numbers together, and all the variables
5x-5-x+(-4)
determiningTheFunctionDomain 5x-x-5+(-4)
We add all the numbers together, and all the variables
4x-9
Back to the equation:
-(4x-9)
4x-(4x-9)-9=0
We get rid of parentheses
4x-4x+9-9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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