1-2(x+1)=3(x+2)

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Solution for 1-2(x+1)=3(x+2) equation: 



1-2(x+1)=3(x+2)

We move all terms to the left:

1-2(x+1)-(3(x+2))=0

We multiply parentheses

-2x-(3(x+2))-2+1=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

-2x-(3x+6)-1=0

We get rid of parentheses

-2x-3x-6-1=0

We add all the numbers together, and all the variables

-5x-7=0

We move all terms containing x to the left, all other terms to the right

-5x=7

x=7/-5

x=-1+2/5

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