1-2(x+3)=8+6(1-x)

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Solution for 1-2(x+3)=8+6(1-x) equation: 



1-2(x+3)=8+6(1-x)

We move all terms to the left:

1-2(x+3)-(8+6(1-x))=0

We add all the numbers together, and all the variables

-2(x+3)-(8+6(-1x+1))+1=0

We multiply parentheses

-2x-(8+6(-1x+1))-6+1=0



We calculate terms in parentheses: -(8+6(-1x+1)), so:

8+6(-1x+1)

determiningTheFunctionDomain
6(-1x+1)+8

We multiply parentheses

-6x+6+8

We add all the numbers together, and all the variables

-6x+14

Back to the equation:

-(-6x+14)



We add all the numbers together, and all the variables

-2x-(-6x+14)-5=0

We get rid of parentheses

-2x+6x-14-5=0

We add all the numbers together, and all the variables

4x-19=0

We move all terms containing x to the left, all other terms to the right

4x=19

x=19/4

x=4+3/4

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