1-2/3(c+1)=1/4(c-5)

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Solution for 1-2/3(c+1)=1/4(c-5) equation:



1-2/3(c+1)=1/4(c-5)
We move all terms to the left:
1-2/3(c+1)-(1/4(c-5))=0
Domain of the equation: 3(c+1)!=0
c∈R
Domain of the equation: 4(c-5))!=0
c∈R
We calculate fractions
(-8cc/(3(c+1)*4(c-5)))+(-3cc/(3(c+1)*4(c-5)))+1=0
We calculate terms in parentheses: +(-8cc/(3(c+1)*4(c-5))), so:
-8cc/(3(c+1)*4(c-5))
We multiply all the terms by the denominator
-8cc
Back to the equation:
+(-8cc)
We calculate terms in parentheses: +(-3cc/(3(c+1)*4(c-5))), so:
-3cc/(3(c+1)*4(c-5))
We multiply all the terms by the denominator
-3cc
Back to the equation:
+(-3cc)
We get rid of parentheses
-8cc-3cc+1=0
We move all terms containing c to the left, all other terms to the right
-8cc-3cc=-1

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