1-2t/-2+4t+1/t=1

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Solution for 1-2t/-2+4t+1/t=1 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

4*t-((2*t)/(-2))+1/t+1 = 1 // - 1

4*t-((2*t)/(-2))+1/t-1+1 = 0

t+4*t+1/t-1+1 = 0

5*t^1+1*t^-1 = 0

(5*t^2+1*t^0)/(t^1) = 0 // * t^2

t^1*(5*t^2+1*t^0) = 0

t^1

5*t^2+1 = 0

5*t^2+1 = 0

DELTA = 0^2-(1*4*5)

DELTA = -20

DELTA < 0

t in { } 

t belongs to the empty set

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