1-2v+7v-11=-8(v-12)+9(v-10)

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Solution for 1-2v+7v-11=-8(v-12)+9(v-10) equation: 



1-2v+7v-11=-8(v-12)+9(v-10)

We move all terms to the left:

1-2v+7v-11-(-8(v-12)+9(v-10))=0

We add all the numbers together, and all the variables

5v-(-8(v-12)+9(v-10))-10=0



We calculate terms in parentheses: -(-8(v-12)+9(v-10)), so:

-8(v-12)+9(v-10)

We multiply parentheses

-8v+9v+96-90

We add all the numbers together, and all the variables

v+6

Back to the equation:

-(v+6)



We get rid of parentheses

5v-v-6-10=0

We add all the numbers together, and all the variables

4v-16=0

We move all terms containing v to the left, all other terms to the right

4v=16

v=16/4

v=4

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