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1-2x=3-2(x+1)
We move all terms to the left:
1-2x-(3-2(x+1))=0
We calculate terms in parentheses: -(3-2(x+1)), so:We get rid of parentheses
3-2(x+1)
determiningTheFunctionDomain -2(x+1)+3
We multiply parentheses
-2x-2+3
We add all the numbers together, and all the variables
-2x+1
Back to the equation:
-(-2x+1)
-2x+2x-1+1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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