1-3((4z+7)-2(z+3))=-(2z-5(z-5))

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Solution for 1-3((4z+7)-2(z+3))=-(2z-5(z-5)) equation: 



1-3((4z+7)-2(z+3))=-(2z-5(z-5))

We move all terms to the left:

1-3((4z+7)-2(z+3))-(-(2z-5(z-5)))=0



We calculate terms in parentheses: -(-(2z-5(z-5))), so:

-(2z-5(z-5))



We calculate terms in parentheses: -(2z-5(z-5)), so:

2z-5(z-5)

We multiply parentheses

2z-5z+25

We add all the numbers together, and all the variables

-3z+25

Back to the equation:

-(-3z+25)



We get rid of parentheses

3z-25

Back to the equation:

-(3z-25)



We get rid of parentheses

-3((4z+7)-2(z+3))-3z+25+1=0

We add all the numbers together, and all the variables

-3z-3((4z+7)-2(z+3))+26=0

We move all terms containing z to the left, all other terms to the right

-3z-3((4z+7)-2(z+3))=-26

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