1-3((4z+7)-2(z+3))=-(2z-5(z-5))

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Solution for 1-3((4z+7)-2(z+3))=-(2z-5(z-5)) equation:



1-3((4z+7)-2(z+3))=-(2z-5(z-5))
We move all terms to the left:
1-3((4z+7)-2(z+3))-(-(2z-5(z-5)))=0
We calculate terms in parentheses: -(-(2z-5(z-5))), so:
-(2z-5(z-5))
We calculate terms in parentheses: -(2z-5(z-5)), so:
2z-5(z-5)
We multiply parentheses
2z-5z+25
We add all the numbers together, and all the variables
-3z+25
Back to the equation:
-(-3z+25)
We get rid of parentheses
3z-25
Back to the equation:
-(3z-25)
We get rid of parentheses
-3((4z+7)-2(z+3))-3z+25+1=0
We add all the numbers together, and all the variables
-3z-3((4z+7)-2(z+3))+26=0
We move all terms containing z to the left, all other terms to the right
-3z-3((4z+7)-2(z+3))=-26

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