1-3(2x-4)=(6-x)-8

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Solution for 1-3(2x-4)=(6-x)-8 equation: 



1-3(2x-4)=(6-x)-8

We move all terms to the left:

1-3(2x-4)-((6-x)-8)=0

We add all the numbers together, and all the variables

-3(2x-4)-((-1x+6)-8)+1=0

We multiply parentheses

-6x-((-1x+6)-8)+12+1=0



We calculate terms in parentheses: -((-1x+6)-8), so:

(-1x+6)-8

We get rid of parentheses

-1x+6-8

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

-(-1x-2)



We add all the numbers together, and all the variables

-6x-(-1x-2)+13=0

We get rid of parentheses

-6x+1x+2+13=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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