1-3(4-a)=4a+5(-2a-1)

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Solution for 1-3(4-a)=4a+5(-2a-1) equation:



1-3(4-a)=4a+5(-2a-1)
We move all terms to the left:
1-3(4-a)-(4a+5(-2a-1))=0
We add all the numbers together, and all the variables
-3(-1a+4)-(4a+5(-2a-1))+1=0
We multiply parentheses
3a-(4a+5(-2a-1))-12+1=0
We calculate terms in parentheses: -(4a+5(-2a-1)), so:
4a+5(-2a-1)
We multiply parentheses
4a-10a-5
We add all the numbers together, and all the variables
-6a-5
Back to the equation:
-(-6a-5)
We add all the numbers together, and all the variables
3a-(-6a-5)-11=0
We get rid of parentheses
3a+6a+5-11=0
We add all the numbers together, and all the variables
9a-6=0
We move all terms containing a to the left, all other terms to the right
9a=6
a=6/9
a=2/3

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