1-3(5b-2)=(7b+3)

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Solution for 1-3(5b-2)=(7b+3) equation: 



1-3(5b-2)=(7b+3)

We move all terms to the left:

1-3(5b-2)-((7b+3))=0

We multiply parentheses

-15b-((7b+3))+6+1=0



We calculate terms in parentheses: -((7b+3)), so:

(7b+3)

We get rid of parentheses

7b+3

Back to the equation:

-(7b+3)



We add all the numbers together, and all the variables

-15b-(7b+3)+7=0

We get rid of parentheses

-15b-7b-3+7=0

We add all the numbers together, and all the variables

-22b+4=0

We move all terms containing b to the left, all other terms to the right

-22b=-4

b=-4/-22

b=2/11

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