1-3(5b-2)=4(7b+3)

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Solution for 1-3(5b-2)=4(7b+3) equation:



1-3(5b-2)=4(7b+3)
We move all terms to the left:
1-3(5b-2)-(4(7b+3))=0
We multiply parentheses
-15b-(4(7b+3))+6+1=0
We calculate terms in parentheses: -(4(7b+3)), so:
4(7b+3)
We multiply parentheses
28b+12
Back to the equation:
-(28b+12)
We add all the numbers together, and all the variables
-15b-(28b+12)+7=0
We get rid of parentheses
-15b-28b-12+7=0
We add all the numbers together, and all the variables
-43b-5=0
We move all terms containing b to the left, all other terms to the right
-43b=5
b=5/-43
b=-5/43

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