1-3(5b-2)=4(7b+3)

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Solution for 1-3(5b-2)=4(7b+3) equation: 



1-3(5b-2)=4(7b+3)

We move all terms to the left:

1-3(5b-2)-(4(7b+3))=0

We multiply parentheses

-15b-(4(7b+3))+6+1=0



We calculate terms in parentheses: -(4(7b+3)), so:

4(7b+3)

We multiply parentheses

28b+12

Back to the equation:

-(28b+12)



We add all the numbers together, and all the variables

-15b-(28b+12)+7=0

We get rid of parentheses

-15b-28b-12+7=0

We add all the numbers together, and all the variables

-43b-5=0

We move all terms containing b to the left, all other terms to the right

-43b=5

b=5/-43

b=-5/43

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