1-3(n-2)=7-n

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Solution for 1-3(n-2)=7-n equation: 



1-3(n-2)=7-n

We move all terms to the left:

1-3(n-2)-(7-n)=0

We add all the numbers together, and all the variables

-3(n-2)-(-1n+7)+1=0

We multiply parentheses

-3n-(-1n+7)+6+1=0

We get rid of parentheses

-3n+1n-7+6+1=0

We add all the numbers together, and all the variables

-2n=0

n=0/-2

n=0

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