1-3(x+2)=1/2(2x-8)+3

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Solution for 1-3(x+2)=1/2(2x-8)+3 equation: 



1-3(x+2)=1/2(2x-8)+3

We move all terms to the left:

1-3(x+2)-(1/2(2x-8)+3)=0



Domain of the equation: 2(2x-8)+3)!=0

x∈R



We multiply parentheses

-3x-(1/2(2x-8)+3)-6+1=0

We multiply all the terms by the denominator


-3x*2(2x-8)-6*2(2x-8)+3)+1*2(2x+3)-(1-8)+3)=0

We add all the numbers together, and all the variables

-3x*2(2x-8)-6*2(2x-8)+3)+1*2(2x+3)-(-7)+3)=0

We add all the numbers together, and all the variables

-3x*2(2x-8)-6*2(2x-8)+3)+1*2(2x=0

Wy multiply elements

-6x^2(2-12x(2+3)+1*2(2x=0

We add all the numbers together, and all the variables

-6x^2(2-12x5+1*2(2x=0

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