1-3(x-5)=(5x-12)/2

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Solution for 1-3(x-5)=(5x-12)/2 equation: 



1-3(x-5)=(5x-12)/2

We move all terms to the left:

1-3(x-5)-((5x-12)/2)=0

We multiply parentheses

-3x-((5x-12)/2)+15+1=0

We multiply all the terms by the denominator


-3x*2)-((5x-12)+15*2)+1*2)=0

We add all the numbers together, and all the variables

-3x*2)-((5x-12)=0

Wy multiply elements

-6x^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-12}=0$

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