1-3(y+7)=3(y-1)

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Solution for 1-3(y+7)=3(y-1) equation: 



1-3(y+7)=3(y-1)

We move all terms to the left:

1-3(y+7)-(3(y-1))=0

We multiply parentheses

-3y-(3(y-1))-21+1=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

-3y-(3y-3)-20=0

We get rid of parentheses

-3y-3y+3-20=0

We add all the numbers together, and all the variables

-6y-17=0

We move all terms containing y to the left, all other terms to the right

-6y=17

y=17/-6

y=-2+5/6

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