1-3(y-2)=1-3y+6

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Solution for 1-3(y-2)=1-3y+6 equation:


Simplifying
1 + -3(y + -2) = 1 + -3y + 6

Reorder the terms:
1 + -3(-2 + y) = 1 + -3y + 6
1 + (-2 * -3 + y * -3) = 1 + -3y + 6
1 + (6 + -3y) = 1 + -3y + 6

Combine like terms: 1 + 6 = 7
7 + -3y = 1 + -3y + 6

Reorder the terms:
7 + -3y = 1 + 6 + -3y

Combine like terms: 1 + 6 = 7
7 + -3y = 7 + -3y

Add '-7' to each side of the equation.
7 + -7 + -3y = 7 + -7 + -3y

Combine like terms: 7 + -7 = 0
0 + -3y = 7 + -7 + -3y
-3y = 7 + -7 + -3y

Combine like terms: 7 + -7 = 0
-3y = 0 + -3y
-3y = -3y

Add '3y' to each side of the equation.
-3y + 3y = -3y + 3y

Combine like terms: -3y + 3y = 0
0 = -3y + 3y

Combine like terms: -3y + 3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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