1-3f-5(f+2)=2(1-4f)+16

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Solution for 1-3f-5(f+2)=2(1-4f)+16 equation: 



1-3f-5(f+2)=2(1-4f)+16

We move all terms to the left:

1-3f-5(f+2)-(2(1-4f)+16)=0

We add all the numbers together, and all the variables

-3f-5(f+2)-(2(-4f+1)+16)+1=0

We multiply parentheses

-3f-5f-(2(-4f+1)+16)-10+1=0



We calculate terms in parentheses: -(2(-4f+1)+16), so:

2(-4f+1)+16

We multiply parentheses

-8f+2+16

We add all the numbers together, and all the variables

-8f+18

Back to the equation:

-(-8f+18)



We add all the numbers together, and all the variables

-8f-(-8f+18)-9=0

We get rid of parentheses

-8f+8f-18-9=0

We add all the numbers together, and all the variables

-27!=0

There is no solution for this equation

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