1-3n(n-2)=7-n

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Solution for 1-3n(n-2)=7-n equation: 



1-3n(n-2)=7-n

We move all terms to the left:

1-3n(n-2)-(7-n)=0

We add all the numbers together, and all the variables

-3n(n-2)-(-1n+7)+1=0

We multiply parentheses

-3n^2+6n-(-1n+7)+1=0

We get rid of parentheses

-3n^2+6n+1n-7+1=0

We add all the numbers together, and all the variables

-3n^2+7n-6=0

a = -3; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·(-3)·(-6)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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