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1-3x(8x-4)=1

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Solution for 1-3x(8x-4)=1 equation:



1-3x(8x-4)=1
We move all terms to the left:
1-3x(8x-4)-(1)=0
We add all the numbers together, and all the variables
-3x(8x-4)=0
We multiply parentheses
-24x^2+12x=0
a = -24; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-24)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{144}=12
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-24}=\frac{-24}{-48} =1/2
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-24}=\frac{0}{-48} =0

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