1-3x2=96

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Solution for 1-3x2=96 equation: 



1-3x^2=96

We move all terms to the left:

1-3x^2-(96)=0

We add all the numbers together, and all the variables

-3x^2-95=0

a = -3; b = 0; c = -95;
Δ = b2-4ac
Δ = 02-4·(-3)·(-95)
Δ = -1140
Delta is less than zero, so there is no solution for the equation

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