1-5(2n-2)=-29-2n

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Solution for 1-5(2n-2)=-29-2n equation: 



1-5(2n-2)=-29-2n

We move all terms to the left:

1-5(2n-2)-(-29-2n)=0

We add all the numbers together, and all the variables

-5(2n-2)-(-2n-29)+1=0

We multiply parentheses

-10n-(-2n-29)+10+1=0

We get rid of parentheses

-10n+2n+29+10+1=0

We add all the numbers together, and all the variables

-8n+40=0

We move all terms containing n to the left, all other terms to the right

-8n=-40

n=-40/-8

n=+5

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