1-5(8t-6)=t+6/10

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Solution for 1-5(8t-6)=t+6/10 equation:



1-5(8t-6)=t+6/10
We move all terms to the left:
1-5(8t-6)-(t+6/10)=0
We add all the numbers together, and all the variables
-5(8t-6)-(+t+6/10)+1=0
We multiply parentheses
-40t-(+t+6/10)+30+1=0
We get rid of parentheses
-40t-t+30+1-6/10=0
We multiply all the terms by the denominator
-40t*10-t*10-6+30*10+1*10=0
We add all the numbers together, and all the variables
-40t*10-t*10+304=0
Wy multiply elements
-400t-10t+304=0
We add all the numbers together, and all the variables
-410t+304=0
We move all terms containing t to the left, all other terms to the right
-410t=-304
t=-304/-410
t=152/205

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