1-5(b+3)=6-(6-1)

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Solution for 1-5(b+3)=6-(6-1) equation: 



1-5(b+3)=6-(6-1)

We move all terms to the left:

1-5(b+3)-(6-(6-1))=0

We add all the numbers together, and all the variables

-5(b+3)+1-(6-5)=0

We add all the numbers together, and all the variables

-5(b+3)=0

We multiply parentheses

-5b-15=0

We move all terms containing b to the left, all other terms to the right

-5b=15

b=15/-5

b=-3

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