1-5(b-7)=-6b+32

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Solution for 1-5(b-7)=-6b+32 equation: 



1-5(b-7)=-6b+32

We move all terms to the left:

1-5(b-7)-(-6b+32)=0

We multiply parentheses

-5b-(-6b+32)+35+1=0

We get rid of parentheses

-5b+6b-32+35+1=0

We add all the numbers together, and all the variables

b+4=0

We move all terms containing b to the left, all other terms to the right

b=-4

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