1-5(n-10)=12(n-4)-8n

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Solution for 1-5(n-10)=12(n-4)-8n equation:



1-5(n-10)=12(n-4)-8n
We move all terms to the left:
1-5(n-10)-(12(n-4)-8n)=0
We multiply parentheses
-5n-(12(n-4)-8n)+50+1=0
We calculate terms in parentheses: -(12(n-4)-8n), so:
12(n-4)-8n
We add all the numbers together, and all the variables
-8n+12(n-4)
We multiply parentheses
-8n+12n-48
We add all the numbers together, and all the variables
4n-48
Back to the equation:
-(4n-48)
We add all the numbers together, and all the variables
-5n-(4n-48)+51=0
We get rid of parentheses
-5n-4n+48+51=0
We add all the numbers together, and all the variables
-9n+99=0
We move all terms containing n to the left, all other terms to the right
-9n=-99
n=-99/-9
n=+11

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