1-5(n-10)=12(n-4)-8n

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Solution for 1-5(n-10)=12(n-4)-8n equation: 



1-5(n-10)=12(n-4)-8n

We move all terms to the left:

1-5(n-10)-(12(n-4)-8n)=0

We multiply parentheses

-5n-(12(n-4)-8n)+50+1=0



We calculate terms in parentheses: -(12(n-4)-8n), so:

12(n-4)-8n

We add all the numbers together, and all the variables

-8n+12(n-4)

We multiply parentheses

-8n+12n-48

We add all the numbers together, and all the variables

4n-48

Back to the equation:

-(4n-48)



We add all the numbers together, and all the variables

-5n-(4n-48)+51=0

We get rid of parentheses

-5n-4n+48+51=0

We add all the numbers together, and all the variables

-9n+99=0

We move all terms containing n to the left, all other terms to the right

-9n=-99

n=-99/-9

n=+11

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