1-5=x-3+2x2

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Solution for 1-5=x-3+2x2 equation: 



1-5=x-3+2x^2

We move all terms to the left:

1-5-(x-3+2x^2)=0

We add all the numbers together, and all the variables

-(x-3+2x^2)-4=0

We get rid of parentheses

-2x^2-x+3-4=0

We add all the numbers together, and all the variables

-2x^2-1x-1=0

a = -2; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·(-2)·(-1)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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