1-5a*4a=-6

Solution for 1-5a*4a=-6 equation:

1-5a*4a=-6

We move all terms to the left:

1-5a*4a-(-6)=0

We add all the numbers together, and all the variables

-5a*4a+7=0

Wy multiply elements

-20a^2+7=0

a = -20; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·(-20)·7
Δ = 560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{560}=\sqrt{16*35}=\sqrt{16}*\sqrt{35}=4\sqrt{35}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{35}}{2*-20}=\frac{0-4\sqrt{35}}{-40}
=-\frac{4\sqrt{35}}{-40}
=-\frac{\sqrt{35}}{-10}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{35}}{2*-20}=\frac{0+4\sqrt{35}}{-40}
=\frac{4\sqrt{35}}{-40}
=\frac{\sqrt{35}}{-10}
$