1-6(2-z)=7

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Solution for 1-6(2-z)=7 equation: 



1-6(2-z)=7

We move all terms to the left:

1-6(2-z)-(7)=0

We add all the numbers together, and all the variables

-6(-1z+2)+1-7=0

We add all the numbers together, and all the variables

-6(-1z+2)-6=0

We multiply parentheses

6z-12-6=0

We add all the numbers together, and all the variables

6z-18=0

We move all terms containing z to the left, all other terms to the right

6z=18

z=18/6

z=3

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