1-6-3(2k+4)=18

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Solution for 1-6-3(2k+4)=18 equation: 



1-6-3(2k+4)=18

We move all terms to the left:

1-6-3(2k+4)-(18)=0

We add all the numbers together, and all the variables

-3(2k+4)-23=0

We multiply parentheses

-6k-12-23=0

We add all the numbers together, and all the variables

-6k-35=0

We move all terms containing k to the left, all other terms to the right

-6k=35

k=35/-6

k=-5+5/6

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