1-6x+x+1=-(x+4)-2(x-8)

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Solution for 1-6x+x+1=-(x+4)-2(x-8) equation: 



1-6x+x+1=-(x+4)-2(x-8)

We move all terms to the left:

1-6x+x+1-(-(x+4)-2(x-8))=0

We add all the numbers together, and all the variables

-5x-(-(x+4)-2(x-8))+2=0



We calculate terms in parentheses: -(-(x+4)-2(x-8)), so:

-(x+4)-2(x-8)

We multiply parentheses

-(x+4)-2x+16

We get rid of parentheses

-x-2x-4+16

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We get rid of parentheses

-5x+3x-12+2=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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