1-7/2x-12=3/x-6

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Solution for 1-7/2x-12=3/x-6 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1-((7/2)*x)-12 = 3/x-6 // - 3/x-6

1-((7/2)*x)-(3/x)-12+6 = 0

(-7/2)*x-3*x^-1-12+1+6 = 0

-7/2*x^1-3*x^-1-5*x^0 = 0

(-7/2*x^2-5*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(-7/2*x^2-5*x^1-3*x^0) = 0

x^1

(-7/2)*x^2-5*x-3 = 0

(-7/2)*x^2-5*x-3 = 0

DELTA = (-5)^2-(-3*4*(-7/2))

DELTA = -17

DELTA < 0

x in { } 

x belongs to the empty set

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