1-8(x-5)-2(x-3)=10-4(2x-3)

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Solution for 1-8(x-5)-2(x-3)=10-4(2x-3) equation: 



1-8(x-5)-2(x-3)=10-4(2x-3)

We move all terms to the left:

1-8(x-5)-2(x-3)-(10-4(2x-3))=0

We multiply parentheses

-8x-2x-(10-4(2x-3))+40+6+1=0



We calculate terms in parentheses: -(10-4(2x-3)), so:

10-4(2x-3)

determiningTheFunctionDomain
-4(2x-3)+10

We multiply parentheses

-8x+12+10

We add all the numbers together, and all the variables

-8x+22

Back to the equation:

-(-8x+22)



We add all the numbers together, and all the variables

-10x-(-8x+22)+47=0

We get rid of parentheses

-10x+8x-22+47=0

We add all the numbers together, and all the variables

-2x+25=0

We move all terms containing x to the left, all other terms to the right

-2x=-25

x=-25/-2

x=12+1/2

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