1-8x=4x-(3-2x)

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Solution for 1-8x=4x-(3-2x) equation: 



1-8x=4x-(3-2x)

We move all terms to the left:

1-8x-(4x-(3-2x))=0

We add all the numbers together, and all the variables

-8x-(4x-(-2x+3))+1=0



We calculate terms in parentheses: -(4x-(-2x+3)), so:

4x-(-2x+3)

We get rid of parentheses

4x+2x-3

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We get rid of parentheses

-8x-6x+3+1=0

We add all the numbers together, and all the variables

-14x+4=0

We move all terms containing x to the left, all other terms to the right

-14x=-4

x=-4/-14

x=2/7

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