1-h/2h=h-1/2h

Solution for 1-h/2h=h-1/2h equation:

1-h/2h=h-1/2h

We move all terms to the left:

1-h/2h-(h-1/2h)=0


Domain of the equation: 2h!=0

h!=0/2

h!=0

h∈R



Domain of the equation: 2h)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

-h/2h-(+h-1/2h)+1=0

We get rid of parentheses

-h/2h-h+1/2h+1=0

We multiply all the terms by the denominator


-h-h*2h+1*2h+1=0

We add all the numbers together, and all the variables

-1h-h*2h+1*2h+1=0

Wy multiply elements

-2h^2-1h+2h+1=0

We add all the numbers together, and all the variables

-2h^2+h+1=0

a = -2; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·(-2)·1
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3}{2*-2}=\frac{-4}{-4}
=1
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3}{2*-2}=\frac{2}{-4}
=-1/2
$