1-log(2x+1)=log(x-1)

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Solution for 1-log(2x+1)=log(x-1) equation:


Simplifying
1 + -1log(2x + 1) = log(x + -1)

Reorder the terms:
1 + -1glo(1 + 2x) = log(x + -1)
1 + (1 * -1glo + 2x * -1glo) = log(x + -1)
1 + (-1glo + -2glox) = log(x + -1)

Reorder the terms:
1 + -1glo + -2glox = glo(-1 + x)
1 + -1glo + -2glox = (-1 * glo + x * glo)
1 + -1glo + -2glox = (-1glo + glox)

Add 'glo' to each side of the equation.
1 + -1glo + glo + -2glox = -1glo + glo + glox

Combine like terms: -1glo + glo = 0
1 + 0 + -2glox = -1glo + glo + glox
1 + -2glox = -1glo + glo + glox

Combine like terms: -1glo + glo = 0
1 + -2glox = 0 + glox
1 + -2glox = glox

Solving
1 + -2glox = glox

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-1glox' to each side of the equation.
1 + -2glox + -1glox = glox + -1glox

Combine like terms: -2glox + -1glox = -3glox
1 + -3glox = glox + -1glox

Combine like terms: glox + -1glox = 0
1 + -3glox = 0

Add '-1' to each side of the equation.
1 + -1 + -3glox = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3glox = 0 + -1
-3glox = 0 + -1

Combine like terms: 0 + -1 = -1
-3glox = -1

Divide each side by '-3lox'.
g = 0.3333333333l-1o-1x-1

Simplifying
g = 0.3333333333l-1o-1x-1

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