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1-x-12x^2=0
We add all the numbers together, and all the variables
-12x^2-1x+1=0
a = -12; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·(-12)·1
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-7}{2*-12}=\frac{-6}{-24} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+7}{2*-12}=\frac{8}{-24} =-1/3 $
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