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1-x/x2=5
We move all terms to the left:
1-x/x2-(5)=0
Domain of the equation: x2!=0We add all the numbers together, and all the variables
x^2!=0/
x^2!=√0
x!=0
x∈R
-x/x2-4=0
We multiply all the terms by the denominator
-x-4*x2=0
We add all the numbers together, and all the variables
-4x^2-1x=0
a = -4; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-4)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-4}=\frac{0}{-8} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-4}=\frac{2}{-8} =-1/4 $
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