1-x2=4(x2-1)

Solution for 1-x2=4(x2-1) equation:

1-x2=4(x2-1)

We move all terms to the left:

1-x2-(4(x2-1))=0

We add all the numbers together, and all the variables

-(4(+x^2-1))-x2+1=0

We add all the numbers together, and all the variables

-1x^2-(4(+x^2-1))+1=0


We calculate terms in parentheses: -(4(+x^2-1)), so:

4(+x^2-1)

We multiply parentheses

4x^2-4

Back to the equation:

-(4x^2-4)


We get rid of parentheses

-1x^2-4x^2+4+1=0

We add all the numbers together, and all the variables

-5x^2+5=0

a = -5; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-5)·5
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*-5}=\frac{-10}{-10}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*-5}=\frac{10}{-10}
=-1
$